(x^(2/3))-(4x^(1/3))-12=0

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Solution for (x^(2/3))-(4x^(1/3))-12=0 equation: 


x in (-oo:+oo)

x^(2/3)-(4*x^(1/3))-12 = 0

x^(2/3)-4*x^(1/3)-12 = 0

t_1 = x^(1/3)

1*t_1^2-4*t_1^1-12 = 0

t_1^2-4*t_1-12 = 0

DELTA = (-4)^2-(-12*1*4)

DELTA = 64

DELTA > 0

t_1 = (64^(1/2)+4)/(1*2) or t_1 = (4-64^(1/2))/(1*2)

t_1 = 6 or t_1 = -2

t_1 = -2

x^(1/3)+2 = 0

1*x^(1/3) = -2 // : 1

x^(1/3) = -2

( -2 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 6

x^(1/3)-6 = 0

1*x^(1/3) = 6 // : 1

x^(1/3) = 6

x^(1/3) = 6 // ^ 3

x = 216

x = 216

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